Solve (-1/3)^2+(pi-3.14)^0-sqrt[3]{-8}*(1/2)^-2

$$( - \frac { 1 } { 3 } ) ^ { 2 } + ( \pi - 3.14 ) ^ { 0 } - \sqrt[ 3 ] { - 8 } \times ( \frac { 1 } { 2 } ) ^ { - 2 }$$

Evaluate

$$\frac{82}{9}\approx 9.111111111$$

Solution Steps

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}+\left(\pi -3.14\right)^{0}-\sqrt[3]{-8}\times \left(\frac{1}{2}\right)^{-2}$$

Calculate \pi -3.14 to the power of 0 and get 1.

$$\frac{1}{9}+1-\sqrt[3]{-8}\times \left(\frac{1}{2}\right)^{-2}$$

Add \frac{1}{9} and 1 to get \frac{10}{9}.

$$\frac{10}{9}-\sqrt[3]{-8}\times \left(\frac{1}{2}\right)^{-2}$$

Calculate \sqrt[3]{-8} and get -2.

$$\frac{10}{9}-\left(-2\times \left(\frac{1}{2}\right)^{-2}\right)$$

Calculate \frac{1}{2} to the power of -2 and get 4.

$$\frac{10}{9}-\left(-2\times 4\right)$$

Multiply -2 and 4 to get -8.

$$\frac{10}{9}-\left(-8\right)$$

The opposite of -8 is 8.

$$\frac{10}{9}+8$$

Add \frac{10}{9} and 8 to get \frac{82}{9}.

$$\frac{82}{9}$$

Factor

$$\frac{2 \cdot 41}{3 ^ {2}} = 9\frac{1}{9} = 9.11111111111111$$