Solve (-1/2)^4div(-1/2)^6]*(-1/2)^6+2^-7=

$$( - \frac { 1 } { 2 } ) ^ { 4 } \div ( - \frac { 1 } { 2 } ) ^ { 6 } ] \cdot ( - \frac { 1 } { 2 } ) ^ { 6 } + 2 ^ { - 7 } =$$

Evaluate

$$4$$

Solution Steps

Rewrite \left(-\frac{1}{2}\right)^{6} as \left(-\frac{1}{2}\right)^{4}\left(-\frac{1}{2}\right)^{2}. Cancel out \left(-\frac{1}{2}\right)^{4} in both numerator and denominator.

$$\frac{1}{\left(-\frac{1}{2}\right)^{2}}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{\frac{1}{4}}$$

Divide 1 by \frac{1}{4} by multiplying 1 by the reciprocal of \frac{1}{4}.

$$1\times 4$$

Multiply 1 and 4 to get 4.

$$4$$

Factor

$$2^{2}$$