Solve (-1/2)^3*(2/3)^2

$$( - \frac { 1 } { 2 } ) ^ { 3 } \times ( \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$-\frac{1}{18}\approx -0.055555556$$

Solution Steps

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$-\frac{1}{8}\times \left(\frac{2}{3}\right)^{2}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{1}{8}\times \frac{4}{9}$$

Multiply -\frac{1}{8} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-4}{8\times 9}$$

Do the multiplications in the fraction \frac{-4}{8\times 9}.

$$\frac{-4}{72}$$

Reduce the fraction \frac{-4}{72} to lowest terms by extracting and canceling out 4.

$$-\frac{1}{18}$$

Factor

$$-\frac{1}{18} = -0.05555555555555555$$