Solve (-1/2)^3*(-4/3)^2

$$( - \frac { 1 } { 2 } ) ^ { 3 } \cdot ( - \frac { 4 } { 3 } ) ^ { 2 }$$

Evaluate

$$-\frac{2}{9}\approx -0.222222222$$

Solution Steps

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$-\frac{1}{8}\left(-\frac{4}{3}\right)^{2}$$

Calculate -\frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$-\frac{1}{8}\times \frac{16}{9}$$

Multiply -\frac{1}{8} times \frac{16}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-16}{8\times 9}$$

Do the multiplications in the fraction \frac{-16}{8\times 9}.

$$\frac{-16}{72}$$

Reduce the fraction \frac{-16}{72} to lowest terms by extracting and canceling out 8.

$$-\frac{2}{9}$$

Factor

$$-\frac{2}{9} = -0.2222222222222222$$