Solve (6^0-2^0)*(6^0+2^0)

$$( { 6 }^{ 0 } - { 2 }^{ 0 } ) \times ( { 6 }^{ 0 } + { 2 }^{ 0 } )$$

Evaluate

$$0$$

Solution Steps

Calculate 6 to the power of 0 and get 1.

$$\left(1-2^{0}\right)\left(6^{0}+2^{0}\right)$$

Calculate 2 to the power of 0 and get 1.

$$\left(1-1\right)\left(6^{0}+2^{0}\right)$$

Subtract 1 from 1 to get 0.

$$0\left(6^{0}+2^{0}\right)$$

Calculate 6 to the power of 0 and get 1.

$$0\left(1+2^{0}\right)$$

Calculate 2 to the power of 0 and get 1.

$$0\left(1+1\right)$$

Add 1 and 1 to get 2.

$$0\times 2$$

Multiply 0 and 2 to get 0.

$$0$$

Factor

$$0$$