Solve (0.5^2+0.2^2+0.2^2+0.5^2)div5

$$( { 0.5 }^{ 2 } + { 0.2 }^{ 2 } + { 0.2 }^{ 2 } + { 0.5 }^{ 2 } ) \div 5$$

Evaluate

$$0.116$$

Solution Steps

Calculate 0.5 to the power of 2 and get 0.25.

$$\frac{0.25+0.2^{2}+0.2^{2}+0.5^{2}}{5}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{0.25+0.04+0.2^{2}+0.5^{2}}{5}$$

Add 0.25 and 0.04 to get 0.29.

$$\frac{0.29+0.2^{2}+0.5^{2}}{5}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{0.29+0.04+0.5^{2}}{5}$$

Add 0.29 and 0.04 to get 0.33.

$$\frac{0.33+0.5^{2}}{5}$$

Calculate 0.5 to the power of 2 and get 0.25.

$$\frac{0.33+0.25}{5}$$

Add 0.33 and 0.25 to get 0.58.

$$\frac{0.58}{5}$$

Expand \frac{0.58}{5} by multiplying both numerator and the denominator by 100.

$$\frac{58}{500}$$

Reduce the fraction \frac{58}{500} to lowest terms by extracting and canceling out 2.

$$\frac{29}{250}$$

Factor

$$\frac{29}{2 \cdot 5 ^ {3}} = 0.116$$