Solve (0.3^2+0.1^2+0.2^2+0.2^2+{0.2}^2)div5=

$$( { 0.3 }^{ 2 } + { 0.1 }^{ 2 } + { 0.2 }^{ 2 } + { 0.2 }^{ 2 } + { 0.2 }^{ 2 } ) \div 5=$$

Evaluate

$$0.044$$

Solution Steps

Calculate 0.3 to the power of 2 and get 0.09.

$$\frac{0.09+0.1^{2}+0.2^{2}+0.2^{2}+0.2^{2}}{5}$$

Calculate 0.1 to the power of 2 and get 0.01.

$$\frac{0.09+0.01+0.2^{2}+0.2^{2}+0.2^{2}}{5}$$

Add 0.09 and 0.01 to get 0.1.

$$\frac{0.1+0.2^{2}+0.2^{2}+0.2^{2}}{5}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{0.1+0.04+0.2^{2}+0.2^{2}}{5}$$

Add 0.1 and 0.04 to get 0.14.

$$\frac{0.14+0.2^{2}+0.2^{2}}{5}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{0.14+0.04+0.2^{2}}{5}$$

Add 0.14 and 0.04 to get 0.18.

$$\frac{0.18+0.2^{2}}{5}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{0.18+0.04}{5}$$

Add 0.18 and 0.04 to get 0.22.

$$\frac{0.22}{5}$$

Expand \frac{0.22}{5} by multiplying both numerator and the denominator by 100.

$$\frac{22}{500}$$

Reduce the fraction \frac{22}{500} to lowest terms by extracting and canceling out 2.

$$\frac{11}{250}$$

Factor

$$\frac{11}{2 \cdot 5 ^ {3}} = 0.044$$