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\left(\sqrt{17}\right)^{2}-3^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
17-3^{2}
The square of \sqrt{17} is 17.
17-9
Calculate 3 to the power of 2 and get 9.
8
Subtract 9 from 17 to get 8.