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\left(\sqrt{11}-1\right)^{2}+2\left(\sqrt{11}-1\right)
Multiply \sqrt{11}-1 and \sqrt{11}-1 to get \left(\sqrt{11}-1\right)^{2}.
\left(\sqrt{11}\right)^{2}-2\sqrt{11}+1+2\left(\sqrt{11}-1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{11}-1\right)^{2}.
11-2\sqrt{11}+1+2\left(\sqrt{11}-1\right)
The square of \sqrt{11} is 11.
12-2\sqrt{11}+2\left(\sqrt{11}-1\right)
Add 11 and 1 to get 12.
12-2\sqrt{11}+2\sqrt{11}-2
Use the distributive property to multiply 2 by \sqrt{11}-1.
12-2
Combine -2\sqrt{11} and 2\sqrt{11} to get 0.
10
Subtract 2 from 12 to get 10.