Solve (sqrt{100}+sqrt{100})*(3+999/20)-5000

$$( \sqrt{ 100 } + \sqrt{ 100 } ) \times (3+ \frac{ 999 }{ 20 } )-5000$$

Evaluate

$$-3941$$

Solution Steps

Calculate the square root of 100 and get 10.

$$\left(10+\sqrt{100}\right)\left(3+\frac{999}{20}\right)-5000$$

Calculate the square root of 100 and get 10.

$$\left(10+10\right)\left(3+\frac{999}{20}\right)-5000$$

Add 10 and 10 to get 20.

$$20\left(3+\frac{999}{20}\right)-5000$$

Convert 3 to fraction \frac{60}{20}.

$$20\left(\frac{60}{20}+\frac{999}{20}\right)-5000$$

Since \frac{60}{20} and \frac{999}{20} have the same denominator, add them by adding their numerators.

$$20\times \frac{60+999}{20}-5000$$

Add 60 and 999 to get 1059.

$$20\times \frac{1059}{20}-5000$$

Cancel out 20 and 20.

$$1059-5000$$

Subtract 5000 from 1059 to get -3941.

$$-3941$$

Factor

$$-3941$$