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\left(\sqrt{10}\right)^{2}-\left(\sqrt{6}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
10-\left(\sqrt{6}\right)^{2}
The square of \sqrt{10} is 10.
10-6
The square of \sqrt{6} is 6.
4
Subtract 6 from 10 to get 4.