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\left(\sqrt{6}\right)^{2}-\left(\sqrt{5}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
6-\left(\sqrt{5}\right)^{2}
The square of \sqrt{6} is 6.
6-5
The square of \sqrt{5} is 5.
1
Subtract 5 from 6 to get 1.