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2\sqrt{5}+\left(\sqrt{5}\right)^{2}-4-2\sqrt{5}
Apply the distributive property by multiplying each term of \sqrt{5}-2 by each term of 2+\sqrt{5}.
2\sqrt{5}+5-4-2\sqrt{5}
The square of \sqrt{5} is 5.
2\sqrt{5}+1-2\sqrt{5}
Subtract 4 from 5 to get 1.
1
Combine 2\sqrt{5} and -2\sqrt{5} to get 0.
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