Solve (sqrt{48}-sqrt{3})*sqrt{3}GBIT

$$( \sqrt { 48 } - \sqrt { 3 } ) \cdot \sqrt { 3 } GBIT$$

Evaluate

$$9BGIT$$

Solution Steps

Factor 48=4^{2}\times 3. Rewrite the square root of the product \sqrt{4^{2}\times 3} as the product of square roots \sqrt{4^{2}}\sqrt{3}. Take the square root of 4^{2}.

$$\left(4\sqrt{3}-\sqrt{3}\right)\sqrt{3}GBIT$$

Combine 4\sqrt{3} and -\sqrt{3} to get 3\sqrt{3}.

$$3\sqrt{3}\sqrt{3}GBIT$$

Multiply \sqrt{3} and \sqrt{3} to get 3.

$$3\times 3GBIT$$

Multiply 3 and 3 to get 9.

$$9GBIT$$

Differentiate w.r.t. T

$$9BGI$$