Solve (sqrt{4})^2-sqrt[3]{8}-sqrt{3^2+4^2}

$$( \sqrt { 4 } ) ^ { 2 } - \sqrt[ 3 ] { 8 } - \sqrt { 3 ^ { 2 } + 4 ^ { 2 } }$$

Evaluate

$$-3$$

Solution Steps

The square of \sqrt{4} is 4.

$$4-\sqrt[3]{8}-\sqrt{3^{2}+4^{2}}$$

Calculate \sqrt[3]{8} and get 2.

$$4-2-\sqrt{3^{2}+4^{2}}$$

Subtract 2 from 4 to get 2.

$$2-\sqrt{3^{2}+4^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$2-\sqrt{9+4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$2-\sqrt{9+16}$$

Add 9 and 16 to get 25.

$$2-\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$2-5$$

Subtract 5 from 2 to get -3.

$$-3$$

Factor

$$-3$$