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\sqrt{3}+\left(\sqrt{3}\right)^{2}-3-3\sqrt{3}
Apply the distributive property by multiplying each term of \sqrt{3}-3 by each term of 1+\sqrt{3}.
\sqrt{3}+3-3-3\sqrt{3}
The square of \sqrt{3} is 3.
\sqrt{3}-3\sqrt{3}
Subtract 3 from 3 to get 0.
-2\sqrt{3}
Combine \sqrt{3} and -3\sqrt{3} to get -2\sqrt{3}.