Evaluate
\sqrt{6}+3-\sqrt{2}-\sqrt{3}\approx 2.303225373
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\left(\sqrt{3}\right)^{2}+\sqrt{3}\sqrt{2}-\sqrt{3}-\sqrt{2}
Apply the distributive property by multiplying each term of \sqrt{3}-1 by each term of \sqrt{3}+\sqrt{2}.
3+\sqrt{3}\sqrt{2}-\sqrt{3}-\sqrt{2}
The square of \sqrt{3} is 3.
3+\sqrt{6}-\sqrt{3}-\sqrt{2}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
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