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2\sqrt{3}+\left(\sqrt{3}\right)^{2}+2+\sqrt{3}
Apply the distributive property by multiplying each term of \sqrt{3}+1 by each term of 2+\sqrt{3}.
2\sqrt{3}+3+2+\sqrt{3}
The square of \sqrt{3} is 3.
2\sqrt{3}+5+\sqrt{3}
Add 3 and 2 to get 5.
3\sqrt{3}+5
Combine 2\sqrt{3} and \sqrt{3} to get 3\sqrt{3}.