Solve (sqrt{27}+sqrt{3})*sqrt{3}=

$$( \sqrt { 27 } + \sqrt { 3 } ) \cdot \sqrt { 3 } =$$

Evaluate

$$12$$

Solution Steps

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$\left(3\sqrt{3}+\sqrt{3}\right)\sqrt{3}$$

Combine 3\sqrt{3} and \sqrt{3} to get 4\sqrt{3}.

$$4\sqrt{3}\sqrt{3}$$

Multiply \sqrt{3} and \sqrt{3} to get 3.

$$4\times 3$$

Multiply 4 and 3 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$