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\left(\sqrt{10}\right)^{2}-3^{2}+1.2
Consider \left(\sqrt{10}-3\right)\left(\sqrt{10}+3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
10-3^{2}+1.2
The square of \sqrt{10} is 10.
10-9+1.2
Calculate 3 to the power of 2 and get 9.
1+1.2
Subtract 9 from 10 to get 1.
2.2
Add 1 and 1.2 to get 2.2.