Evaluate
2\sqrt{10}+11\approx 17.32455532
Expand
2 \sqrt{10} + 11 = 17.32455532
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\left(\sqrt{10}\right)^{2}+2\sqrt{10}+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{10}+1\right)^{2}.
10+2\sqrt{10}+1
The square of \sqrt{10} is 10.
11+2\sqrt{10}
Add 10 and 1 to get 11.
\left(\sqrt{10}\right)^{2}+2\sqrt{10}+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{10}+1\right)^{2}.
10+2\sqrt{10}+1
The square of \sqrt{10} is 10.
11+2\sqrt{10}
Add 10 and 1 to get 11.
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