Solve (7/6+9/4)*12/11

$$( \frac{ 7 }{ 6 } + \frac{ 9 }{ 4 } ) \times \frac{ 12 }{ 11 }$$

Evaluate

$$\frac{41}{11}\approx 3.727272727$$

Solution Steps

Least common multiple of 6 and 4 is 12. Convert \frac{7}{6} and \frac{9}{4} to fractions with denominator 12.

$$\left(\frac{14}{12}+\frac{27}{12}\right)\times \frac{12}{11}$$

Since \frac{14}{12} and \frac{27}{12} have the same denominator, add them by adding their numerators.

$$\frac{14+27}{12}\times \frac{12}{11}$$

Add 14 and 27 to get 41.

$$\frac{41}{12}\times \frac{12}{11}$$

Multiply \frac{41}{12} times \frac{12}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{41\times 12}{12\times 11}$$

Cancel out 12 in both numerator and denominator.

$$\frac{41}{11}$$

Factor

$$\frac{41}{11} = 3\frac{8}{11} = 3.727272727272727$$