Solve (4(400)/4(43200)+800/(7407+13333+16666+frac{4(43200){12})})

$$( \frac{ 4(400) }{ 4(43200) } + \frac{ 800 }{ (7407+13333+16666+ \frac{ 4(43200) }{ 12 } ) } )$$

Evaluate

$$\frac{69103}{2797524}\approx 0.024701486$$

Solution Steps

Cancel out 4\times 400 in both numerator and denominator.

$$\frac{1}{108}+\frac{800}{7407+13333+16666+\frac{4\times 43200}{12}}$$

Add 7407 and 13333 to get 20740.

$$\frac{1}{108}+\frac{800}{20740+16666+\frac{4\times 43200}{12}}$$

Add 20740 and 16666 to get 37406.

$$\frac{1}{108}+\frac{800}{37406+\frac{4\times 43200}{12}}$$

Multiply 4 and 43200 to get 172800.

$$\frac{1}{108}+\frac{800}{37406+\frac{172800}{12}}$$

Divide 172800 by 12 to get 14400.

$$\frac{1}{108}+\frac{800}{37406+14400}$$

Add 37406 and 14400 to get 51806.

$$\frac{1}{108}+\frac{800}{51806}$$

Reduce the fraction \frac{800}{51806} to lowest terms by extracting and canceling out 2.

$$\frac{1}{108}+\frac{400}{25903}$$

Least common multiple of 108 and 25903 is 2797524. Convert \frac{1}{108} and \frac{400}{25903} to fractions with denominator 2797524.

$$\frac{25903}{2797524}+\frac{43200}{2797524}$$

Since \frac{25903}{2797524} and \frac{43200}{2797524} have the same denominator, add them by adding their numerators.

$$\frac{25903+43200}{2797524}$$

Add 25903 and 43200 to get 69103.

$$\frac{69103}{2797524}$$

Factor

$$\frac{19 \cdot 3637}{2 ^ {2} \cdot 3 ^ {3} \cdot 25903} = 0.024701486028359365$$