Solve (4/3+1/2)div(5-3/4)=

$$( \frac{ 4 }{ 3 } + \frac{ 1 }{ 2 } ) \div (5- \frac{ 3 }{ 4 } )=$$

Evaluate

$$\frac{22}{51}\approx 0.431372549$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{4}{3} and \frac{1}{2} to fractions with denominator 6.

$$\frac{\frac{8}{6}+\frac{3}{6}}{5-\frac{3}{4}}$$

Since \frac{8}{6} and \frac{3}{6} have the same denominator, add them by adding their numerators.

$$\frac{\frac{8+3}{6}}{5-\frac{3}{4}}$$

Add 8 and 3 to get 11.

$$\frac{\frac{11}{6}}{5-\frac{3}{4}}$$

Convert 5 to fraction \frac{20}{4}.

$$\frac{\frac{11}{6}}{\frac{20}{4}-\frac{3}{4}}$$

Since \frac{20}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{11}{6}}{\frac{20-3}{4}}$$

Subtract 3 from 20 to get 17.

$$\frac{\frac{11}{6}}{\frac{17}{4}}$$

Divide \frac{11}{6} by \frac{17}{4} by multiplying \frac{11}{6} by the reciprocal of \frac{17}{4}.

$$\frac{11}{6}\times \frac{4}{17}$$

Multiply \frac{11}{6} times \frac{4}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{11\times 4}{6\times 17}$$

Do the multiplications in the fraction \frac{11\times 4}{6\times 17}.

$$\frac{44}{102}$$

Reduce the fraction \frac{44}{102} to lowest terms by extracting and canceling out 2.

$$\frac{22}{51}$$

Factor

$$\frac{2 \cdot 11}{3 \cdot 17} = 0.43137254901960786$$