Solve (3/8-2/3)*48-(5-7

$$( \frac{ 3 }{ 8 } - \frac{ 2 }{ 3 } ) \times 48-(5-7$$

Evaluate

$$-12$$

Solution Steps

Least common multiple of 8 and 3 is 24. Convert \frac{3}{8} and \frac{2}{3} to fractions with denominator 24.

$$\left(\frac{9}{24}-\frac{16}{24}\right)\times 48-\left(5-7\right)$$

Since \frac{9}{24} and \frac{16}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-16}{24}\times 48-\left(5-7\right)$$

Subtract 16 from 9 to get -7.

$$-\frac{7}{24}\times 48-\left(5-7\right)$$

Express -\frac{7}{24}\times 48 as a single fraction.

$$\frac{-7\times 48}{24}-\left(5-7\right)$$

Multiply -7 and 48 to get -336.

$$\frac{-336}{24}-\left(5-7\right)$$

Divide -336 by 24 to get -14.

$$-14-\left(5-7\right)$$

Subtract 7 from 5 to get -2.

$$-14-\left(-2\right)$$

The opposite of -2 is 2.

$$-14+2$$

Add -14 and 2 to get -12.

$$-12$$

Factor

$$-12$$