Solve (3/5+13/16)*16/39

$$( \frac{ 3 }{ 5 } + \frac{ 13 }{ 16 } ) \times \frac{ 16 }{ 39 }$$

Evaluate

$$\frac{113}{195}\approx 0.579487179$$

Solution Steps

Least common multiple of 5 and 16 is 80. Convert \frac{3}{5} and \frac{13}{16} to fractions with denominator 80.

$$\left(\frac{48}{80}+\frac{65}{80}\right)\times \frac{16}{39}$$

Since \frac{48}{80} and \frac{65}{80} have the same denominator, add them by adding their numerators.

$$\frac{48+65}{80}\times \frac{16}{39}$$

Add 48 and 65 to get 113.

$$\frac{113}{80}\times \frac{16}{39}$$

Multiply \frac{113}{80} times \frac{16}{39} by multiplying numerator times numerator and denominator times denominator.

$$\frac{113\times 16}{80\times 39}$$

Do the multiplications in the fraction \frac{113\times 16}{80\times 39}.

$$\frac{1808}{3120}$$

Reduce the fraction \frac{1808}{3120} to lowest terms by extracting and canceling out 16.

$$\frac{113}{195}$$

Factor

$$\frac{113}{3 \cdot 5 \cdot 13} = 0.5794871794871795$$