Solve (3/20*12/19)+(12/20*3/19)

$$( \frac{ 3 }{ 20 } \times \frac{ 12 }{ 19 } )+( \frac{ 12 }{ 20 } \times \frac{ 3 }{ 19 } )$$

Evaluate

$$\frac{18}{95}\approx 0.189473684$$

Solution Steps

Multiply \frac{3}{20} times \frac{12}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 12}{20\times 19}+\frac{12}{20}\times \frac{3}{19}$$

Do the multiplications in the fraction \frac{3\times 12}{20\times 19}.

$$\frac{36}{380}+\frac{12}{20}\times \frac{3}{19}$$

Reduce the fraction \frac{36}{380} to lowest terms by extracting and canceling out 4.

$$\frac{9}{95}+\frac{12}{20}\times \frac{3}{19}$$

Reduce the fraction \frac{12}{20} to lowest terms by extracting and canceling out 4.

$$\frac{9}{95}+\frac{3}{5}\times \frac{3}{19}$$

Multiply \frac{3}{5} times \frac{3}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{95}+\frac{3\times 3}{5\times 19}$$

Do the multiplications in the fraction \frac{3\times 3}{5\times 19}.

$$\frac{9}{95}+\frac{9}{95}$$

Since \frac{9}{95} and \frac{9}{95} have the same denominator, add them by adding their numerators.

$$\frac{9+9}{95}$$

Add 9 and 9 to get 18.

$$\frac{18}{95}$$

Factor

$$\frac{2 \cdot 3 ^ {2}}{5 \cdot 19} = 0.18947368421052632$$