Solve (2/3+2/9)*3-7/5

$$( \frac{ 2 }{ 3 } + \frac{ 2 }{ 9 } ) \times 3- \frac{ 7 }{ 5 }$$

Evaluate

$$\frac{19}{15}\approx 1.266666667$$

Solution Steps

Least common multiple of 3 and 9 is 9. Convert \frac{2}{3} and \frac{2}{9} to fractions with denominator 9.

$$\left(\frac{6}{9}+\frac{2}{9}\right)\times 3-\frac{7}{5}$$

Since \frac{6}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$\frac{6+2}{9}\times 3-\frac{7}{5}$$

Add 6 and 2 to get 8.

$$\frac{8}{9}\times 3-\frac{7}{5}$$

Express \frac{8}{9}\times 3 as a single fraction.

$$\frac{8\times 3}{9}-\frac{7}{5}$$

Multiply 8 and 3 to get 24.

$$\frac{24}{9}-\frac{7}{5}$$

Reduce the fraction \frac{24}{9} to lowest terms by extracting and canceling out 3.

$$\frac{8}{3}-\frac{7}{5}$$

Least common multiple of 3 and 5 is 15. Convert \frac{8}{3} and \frac{7}{5} to fractions with denominator 15.

$$\frac{40}{15}-\frac{21}{15}$$

Since \frac{40}{15} and \frac{21}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40-21}{15}$$

Subtract 21 from 40 to get 19.

$$\frac{19}{15}$$

Factor

$$\frac{19}{3 \cdot 5} = 1\frac{4}{15} = 1.2666666666666666$$