Solve (19/8+11/12)5/48

$$( \frac{ 19 }{ 8 } + \frac{ 11 }{ 12 } ) \frac{ 5 }{ 48 }$$

Evaluate

$$\frac{395}{1152}\approx 0.342881944$$

Solution Steps

Least common multiple of 8 and 12 is 24. Convert \frac{19}{8} and \frac{11}{12} to fractions with denominator 24.

$$\left(\frac{57}{24}+\frac{22}{24}\right)\times \frac{5}{48}$$

Since \frac{57}{24} and \frac{22}{24} have the same denominator, add them by adding their numerators.

$$\frac{57+22}{24}\times \frac{5}{48}$$

Add 57 and 22 to get 79.

$$\frac{79}{24}\times \frac{5}{48}$$

Multiply \frac{79}{24} times \frac{5}{48} by multiplying numerator times numerator and denominator times denominator.

$$\frac{79\times 5}{24\times 48}$$

Do the multiplications in the fraction \frac{79\times 5}{24\times 48}.

$$\frac{395}{1152}$$

Factor

$$\frac{5 \cdot 79}{2 ^ {7} \cdot 3 ^ {2}} = 0.3428819444444444$$