Solve (-2y-1/3)div3-y/2=-5/6

$$( \frac{ -2y-1 }{ 3 } ) \div 3- \frac{ y }{ 2 } =- \frac{ 5 }{ 6 }$$

Solve for y

$$y=1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,2,6.

$$2\times \frac{-2y-1}{3}-3y=-5$$

Express 2\times \frac{-2y-1}{3} as a single fraction.

$$\frac{2\left(-2y-1\right)}{3}-3y=-5$$

Use the distributive property to multiply 2 by -2y-1.

$$\frac{-4y-2}{3}-3y=-5$$

Divide each term of -4y-2 by 3 to get -\frac{4}{3}y-\frac{2}{3}.

$$-\frac{4}{3}y-\frac{2}{3}-3y=-5$$

Combine -\frac{4}{3}y and -3y to get -\frac{13}{3}y.

$$-\frac{13}{3}y-\frac{2}{3}=-5$$

Add \frac{2}{3} to both sides.

$$-\frac{13}{3}y=-5+\frac{2}{3}$$

Convert -5 to fraction -\frac{15}{3}.

$$-\frac{13}{3}y=-\frac{15}{3}+\frac{2}{3}$$

Since -\frac{15}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$-\frac{13}{3}y=\frac{-15+2}{3}$$

Add -15 and 2 to get -13.

$$-\frac{13}{3}y=-\frac{13}{3}$$

Multiply both sides by -\frac{3}{13}, the reciprocal of -\frac{13}{3}.

$$y=-\frac{13}{3}\left(-\frac{3}{13}\right)$$

Multiply -\frac{13}{3} times -\frac{3}{13} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-13\left(-3\right)}{3\times 13}$$

Do the multiplications in the fraction \frac{-13\left(-3\right)}{3\times 13}.

$$y=\frac{39}{39}$$

Divide 39 by 39 to get 1.

$$y=1$$