Solve (frac{k^{3}f^4}{k^2j^-1})^-4

$$( \frac { k ^ { 3 } f ^ { 4 } } { k ^ { 2 } j ^ { - 1 } } ) ^ { - 4 }$$

Evaluate

$$\frac{1}{\left(jk\right)^{4}f^{16}}$$

Solution Steps

Cancel out k^{2} in both numerator and denominator.

$$\left(\frac{kf^{4}}{\frac{1}{j}}\right)^{-4}$$

Divide kf^{4} by \frac{1}{j} by multiplying kf^{4} by the reciprocal of \frac{1}{j}.

$$\left(kf^{4}j\right)^{-4}$$

Expand \left(kf^{4}j\right)^{-4}.

$$k^{-4}\left(f^{4}\right)^{-4}j^{-4}$$

To raise a power to another power, multiply the exponents. Multiply 4 and -4 to get -16.

$$k^{-4}f^{-16}j^{-4}$$

Expand

$$\frac{1}{\left(jk\right)^{4}f^{16}}$$

Solution Steps

Cancel out k^{2} in both numerator and denominator.

$$\left(\frac{kf^{4}}{\frac{1}{j}}\right)^{-4}$$

Divide kf^{4} by \frac{1}{j} by multiplying kf^{4} by the reciprocal of \frac{1}{j}.

$$\left(kf^{4}j\right)^{-4}$$

Expand \left(kf^{4}j\right)^{-4}.

$$k^{-4}\left(f^{4}\right)^{-4}j^{-4}$$

To raise a power to another power, multiply the exponents. Multiply 4 and -4 to get -16.

$$k^{-4}f^{-16}j^{-4}$$