Solve (9/16*4/12)+(9/16*-3/9)

$$( \frac { 9 } { 16 } \times \frac { 4 } { 12 } ) + ( \frac { 9 } { 16 } \times \frac { - 3 } { 9 } )$$

Evaluate

$$0$$

Solution Steps

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{9}{16}\times \frac{1}{3}+\frac{9}{16}\times \frac{-3}{9}$$

Multiply \frac{9}{16} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 1}{16\times 3}+\frac{9}{16}\times \frac{-3}{9}$$

Do the multiplications in the fraction \frac{9\times 1}{16\times 3}.

$$\frac{9}{48}+\frac{9}{16}\times \frac{-3}{9}$$

Reduce the fraction \frac{9}{48} to lowest terms by extracting and canceling out 3.

$$\frac{3}{16}+\frac{9}{16}\times \frac{-3}{9}$$

Reduce the fraction \frac{-3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{3}{16}+\frac{9}{16}\left(-\frac{1}{3}\right)$$

Multiply \frac{9}{16} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{16}+\frac{9\left(-1\right)}{16\times 3}$$

Do the multiplications in the fraction \frac{9\left(-1\right)}{16\times 3}.

$$\frac{3}{16}+\frac{-9}{48}$$

Reduce the fraction \frac{-9}{48} to lowest terms by extracting and canceling out 3.

$$\frac{3}{16}-\frac{3}{16}$$

Subtract \frac{3}{16} from \frac{3}{16} to get 0.

$$0$$

Factor

$$0$$