Solve (8/3)(5/2)(-7/9)=

$$( \frac { 8 } { 3 } ) ( \frac { 5 } { 2 } ) ( - \frac { 7 } { 9 } ) =$$

Evaluate

$$-\frac{140}{27}\approx -5.185185185$$

Solution Steps

Multiply \frac{8}{3} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 5}{3\times 2}\left(-\frac{7}{9}\right)$$

Do the multiplications in the fraction \frac{8\times 5}{3\times 2}.

$$\frac{40}{6}\left(-\frac{7}{9}\right)$$

Reduce the fraction \frac{40}{6} to lowest terms by extracting and canceling out 2.

$$\frac{20}{3}\left(-\frac{7}{9}\right)$$

Multiply \frac{20}{3} times -\frac{7}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\left(-7\right)}{3\times 9}$$

Do the multiplications in the fraction \frac{20\left(-7\right)}{3\times 9}.

$$\frac{-140}{27}$$

Fraction \frac{-140}{27} can be rewritten as -\frac{140}{27} by extracting the negative sign.

$$-\frac{140}{27}$$

Factor

$$-\frac{140}{27} = -5\frac{5}{27} = -5.185185185185185$$