Solve (7/9)*(27/8)geq15/198

$$( \frac { 7 } { 9 } ) \cdot ( \frac { 27 } { 8 } ) \geq \frac { 15 } { 198 }$$

Verify

Solution Steps

Multiply \frac{7}{9} times \frac{27}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 27}{9\times 8}\geq \frac{15}{198}$$

Do the multiplications in the fraction \frac{7\times 27}{9\times 8}.

$$\frac{189}{72}\geq \frac{15}{198}$$

Reduce the fraction \frac{189}{72} to lowest terms by extracting and canceling out 9.

$$\frac{21}{8}\geq \frac{15}{198}$$

Reduce the fraction \frac{15}{198} to lowest terms by extracting and canceling out 3.

$$\frac{21}{8}\geq \frac{5}{66}$$

Least common multiple of 8 and 66 is 264. Convert \frac{21}{8} and \frac{5}{66} to fractions with denominator 264.

$$\frac{693}{264}\geq \frac{20}{264}$$

Compare \frac{693}{264} and \frac{20}{264}.

$$\text{true}$$