Solve (7/6)^2-2*7/6-3

$$( \frac { 7 } { 6 } ) ^ { 2 } - 2 \times \frac { 7 } { 6 } - 3$$

Evaluate

$$-\frac{143}{36}\approx -3.972222222$$

Solution Steps

Calculate \frac{7}{6} to the power of 2 and get \frac{49}{36}.

$$\frac{49}{36}-2\times \frac{7}{6}-3$$

Express 2\times \frac{7}{6} as a single fraction.

$$\frac{49}{36}-\frac{2\times 7}{6}-3$$

Multiply 2 and 7 to get 14.

$$\frac{49}{36}-\frac{14}{6}-3$$

Reduce the fraction \frac{14}{6} to lowest terms by extracting and canceling out 2.

$$\frac{49}{36}-\frac{7}{3}-3$$

Least common multiple of 36 and 3 is 36. Convert \frac{49}{36} and \frac{7}{3} to fractions with denominator 36.

$$\frac{49}{36}-\frac{84}{36}-3$$

Since \frac{49}{36} and \frac{84}{36} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-84}{36}-3$$

Subtract 84 from 49 to get -35.

$$-\frac{35}{36}-3$$

Convert 3 to fraction \frac{108}{36}.

$$-\frac{35}{36}-\frac{108}{36}$$

Since -\frac{35}{36} and \frac{108}{36} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-35-108}{36}$$

Subtract 108 from -35 to get -143.

$$-\frac{143}{36}$$

Factor

$$-\frac{143}{36} = -3\frac{35}{36} = -3.9722222222222223$$