Solve (7/1-3/4)(3/1-21/2)

$$( \frac { 7 } { 1 } - \frac { 3 } { 4 } ) ( \frac { 3 } { 1 } - 2 \frac { 1 } { 2 } )$$

Evaluate

$$\frac{25}{8}=3.125$$

Solution Steps

Anything divided by one gives itself.

$$\left(7-\frac{3}{4}\right)\left(\frac{3}{1}-\frac{2\times 2+1}{2}\right)$$

Convert 7 to fraction \frac{28}{4}.

$$\left(\frac{28}{4}-\frac{3}{4}\right)\left(\frac{3}{1}-\frac{2\times 2+1}{2}\right)$$

Since \frac{28}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-3}{4}\left(\frac{3}{1}-\frac{2\times 2+1}{2}\right)$$

Subtract 3 from 28 to get 25.

$$\frac{25}{4}\left(\frac{3}{1}-\frac{2\times 2+1}{2}\right)$$

Anything divided by one gives itself.

$$\frac{25}{4}\left(3-\frac{2\times 2+1}{2}\right)$$

Multiply 2 and 2 to get 4.

$$\frac{25}{4}\left(3-\frac{4+1}{2}\right)$$

Add 4 and 1 to get 5.

$$\frac{25}{4}\left(3-\frac{5}{2}\right)$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{25}{4}\left(\frac{6}{2}-\frac{5}{2}\right)$$

Since \frac{6}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25}{4}\times \frac{6-5}{2}$$

Subtract 5 from 6 to get 1.

$$\frac{25}{4}\times \frac{1}{2}$$

Multiply \frac{25}{4} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25\times 1}{4\times 2}$$

Do the multiplications in the fraction \frac{25\times 1}{4\times 2}.

$$\frac{25}{8}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {3}} = 3\frac{1}{8} = 3.125$$