Solve (frac{6.02*10^23text{moleculesofwate}r}{1text{moleofwater}})=

$$( \frac { 6.02 \times 10 ^ { 23 } \text { molecules of wate } r } { 1 \text { mole of water } } ) =$$

Evaluate

$$602000000000000000000000eclsu$$

Solution Steps

Multiply o and o to get o^{2}.

$$\frac{6.02\times 10^{23}mo^{2}leculesfwater}{1moleofwater}$$

Multiply l and l to get l^{2}.

$$\frac{6.02\times 10^{23}mo^{2}l^{2}ecuesfwater}{1moleofwater}$$

Multiply e and e to get e^{2}.

$$\frac{6.02\times 10^{23}mo^{2}l^{2}e^{2}cusfwater}{1moleofwater}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{6.02\times 10^{23}mo^{2}l^{2}e^{3}cusfwatr}{1moleofwater}$$

Multiply o and o to get o^{2}.

$$\frac{6.02\times 10^{23}mo^{2}l^{2}e^{3}cusfwatr}{1mo^{2}lefwater}$$

Multiply e and e to get e^{2}.

$$\frac{6.02\times 10^{23}mo^{2}l^{2}e^{3}cusfwatr}{1mo^{2}le^{2}fwatr}$$

Cancel out e^{2}aflmrtwo^{2} in both numerator and denominator.

$$6.02e\times 10^{23}clsu$$

Calculate 10 to the power of 23 and get 100000000000000000000000.

$$6.02e\times 100000000000000000000000clsu$$

Multiply 6.02 and 100000000000000000000000 to get 602000000000000000000000.

$$602000000000000000000000eclsu$$

Differentiate w.r.t. c

$$602000000000000000000000elsu$$