Solve (frac{6a^{-7}b^5}{18a^2b^-4})^0

$$( \frac { 6 a ^ { - 7 } b ^ { 5 } } { 18 a ^ { 2 } b ^ { - 4 } } ) ^ { 0 }$$

Evaluate

$$1$$

Solution Steps

Cancel out 6 in both numerator and denominator.

$$\left(\frac{a^{-7}b^{5}}{3b^{-4}a^{2}}\right)^{0}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\left(\frac{a^{-7}b^{9}}{3a^{2}}\right)^{0}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\left(\frac{b^{9}}{3a^{9}}\right)^{0}$$

Calculate \frac{b^{9}}{3a^{9}} to the power of 0 and get 1.

$$1$$

Factor

$$1$$