Solve (6/8+3/10-7/3)=

$$( \frac { 6 } { 8 } + \frac { 3 } { 10 } - \frac { 7 } { 3 } ) =$$

Evaluate

$$-\frac{77}{60}\approx -1.283333333$$

Solution Steps

Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.

$$\frac{3}{4}+\frac{3}{10}-\frac{7}{3}$$

Least common multiple of 4 and 10 is 20. Convert \frac{3}{4} and \frac{3}{10} to fractions with denominator 20.

$$\frac{15}{20}+\frac{6}{20}-\frac{7}{3}$$

Since \frac{15}{20} and \frac{6}{20} have the same denominator, add them by adding their numerators.

$$\frac{15+6}{20}-\frac{7}{3}$$

Add 15 and 6 to get 21.

$$\frac{21}{20}-\frac{7}{3}$$

Least common multiple of 20 and 3 is 60. Convert \frac{21}{20} and \frac{7}{3} to fractions with denominator 60.

$$\frac{63}{60}-\frac{140}{60}$$

Since \frac{63}{60} and \frac{140}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-140}{60}$$

Subtract 140 from 63 to get -77.

$$-\frac{77}{60}$$

Factor

$$-\frac{77}{60} = -1\frac{17}{60} = -1.2833333333333334$$