Solve (6/3*3-0.75*1/6)*1/3-9=

$$( \frac { 6 } { 3 } \cdot 3 - 0.75 \cdot \frac { 1 } { 6 } ) \cdot \frac { 1 } { 3 } - 9 =$$

Evaluate

$$-\frac{169}{24}\approx -7.041666667$$

Solution Steps

Divide 6 by 3 to get 2.

$$\left(2\times 3-0.75\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Multiply 2 and 3 to get 6.

$$\left(6-0.75\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Convert decimal number 0.75 to fraction \frac{75}{100}. Reduce the fraction \frac{75}{100} to lowest terms by extracting and canceling out 25.

$$\left(6-\frac{3}{4}\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Multiply \frac{3}{4} times \frac{1}{6} by multiplying numerator times numerator and denominator times denominator.

$$\left(6-\frac{3\times 1}{4\times 6}\right)\times \frac{1}{3}-9$$

Do the multiplications in the fraction \frac{3\times 1}{4\times 6}.

$$\left(6-\frac{3}{24}\right)\times \frac{1}{3}-9$$

Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.

$$\left(6-\frac{1}{8}\right)\times \frac{1}{3}-9$$

Convert 6 to fraction \frac{48}{8}.

$$\left(\frac{48}{8}-\frac{1}{8}\right)\times \frac{1}{3}-9$$

Since \frac{48}{8} and \frac{1}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-1}{8}\times \frac{1}{3}-9$$

Subtract 1 from 48 to get 47.

$$\frac{47}{8}\times \frac{1}{3}-9$$

Multiply \frac{47}{8} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{47\times 1}{8\times 3}-9$$

Do the multiplications in the fraction \frac{47\times 1}{8\times 3}.

$$\frac{47}{24}-9$$

Convert 9 to fraction \frac{216}{24}.

$$\frac{47}{24}-\frac{216}{24}$$

Since \frac{47}{24} and \frac{216}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{47-216}{24}$$

Subtract 216 from 47 to get -169.

$$-\frac{169}{24}$$

Factor

$$-\frac{169}{24} = -7\frac{1}{24} = -7.041666666666667$$