Solve (5/9)^3+(7/12)+3/4=

$$( \frac { 5 } { 9 } ) ^ { 3 } + ( \frac { 7 } { 12 } ) + \frac { 3 } { 4 } =$$

Evaluate

$$\frac{1097}{729}\approx 1.504801097$$

Solution Steps

Calculate \frac{5}{9} to the power of 3 and get \frac{125}{729}.

$$\frac{125}{729}+\frac{7}{12}+\frac{3}{4}$$

Least common multiple of 729 and 12 is 2916. Convert \frac{125}{729} and \frac{7}{12} to fractions with denominator 2916.

$$\frac{500}{2916}+\frac{1701}{2916}+\frac{3}{4}$$

Since \frac{500}{2916} and \frac{1701}{2916} have the same denominator, add them by adding their numerators.

$$\frac{500+1701}{2916}+\frac{3}{4}$$

Add 500 and 1701 to get 2201.

$$\frac{2201}{2916}+\frac{3}{4}$$

Least common multiple of 2916 and 4 is 2916. Convert \frac{2201}{2916} and \frac{3}{4} to fractions with denominator 2916.

$$\frac{2201}{2916}+\frac{2187}{2916}$$

Since \frac{2201}{2916} and \frac{2187}{2916} have the same denominator, add them by adding their numerators.

$$\frac{2201+2187}{2916}$$

Add 2201 and 2187 to get 4388.

$$\frac{4388}{2916}$$

Reduce the fraction \frac{4388}{2916} to lowest terms by extracting and canceling out 4.

$$\frac{1097}{729}$$

Factor

$$\frac{1097}{3 ^ {6}} = 1\frac{368}{729} = 1.50480109739369$$