Solve (5/9+13/1+1/9)

$$( \frac { 5 } { 9 } + \frac { 13 } { 1 } + \frac { 1 } { 9 } )$$

Evaluate

$$\frac{41}{3}\approx 13.666666667$$

Solution Steps

Anything divided by one gives itself.

$$\frac{5}{9}+13+\frac{1}{9}$$

Convert 13 to fraction \frac{117}{9}.

$$\frac{5}{9}+\frac{117}{9}+\frac{1}{9}$$

Since \frac{5}{9} and \frac{117}{9} have the same denominator, add them by adding their numerators.

$$\frac{5+117}{9}+\frac{1}{9}$$

Add 5 and 117 to get 122.

$$\frac{122}{9}+\frac{1}{9}$$

Since \frac{122}{9} and \frac{1}{9} have the same denominator, add them by adding their numerators.

$$\frac{122+1}{9}$$

Add 122 and 1 to get 123.

$$\frac{123}{9}$$

Reduce the fraction \frac{123}{9} to lowest terms by extracting and canceling out 3.

$$\frac{41}{3}$$

Factor

$$\frac{41}{3} = 13\frac{2}{3} = 13.666666666666666$$