Solve (5/22-8/11)*41/5

$$( \frac { 5 } { 22 } - \frac { 8 } { 11 } ) \cdot \frac { 41 } { 5 }$$

Evaluate

$$-\frac{41}{10}=-4.1$$

Solution Steps

Least common multiple of 22 and 11 is 22. Convert \frac{5}{22} and \frac{8}{11} to fractions with denominator 22.

$$\left(\frac{5}{22}-\frac{16}{22}\right)\times \frac{41}{5}$$

Since \frac{5}{22} and \frac{16}{22} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-16}{22}\times \frac{41}{5}$$

Subtract 16 from 5 to get -11.

$$\frac{-11}{22}\times \frac{41}{5}$$

Reduce the fraction \frac{-11}{22} to lowest terms by extracting and canceling out 11.

$$-\frac{1}{2}\times \frac{41}{5}$$

Multiply -\frac{1}{2} times \frac{41}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-41}{2\times 5}$$

Do the multiplications in the fraction \frac{-41}{2\times 5}.

$$\frac{-41}{10}$$

Fraction \frac{-41}{10} can be rewritten as -\frac{41}{10} by extracting the negative sign.

$$-\frac{41}{10}$$

Factor

$$-\frac{41}{10} = -4\frac{1}{10} = -4.1$$