Solve (5/2-3):(11/3-2/3)

$$( \frac { 5 } { 2 } - 3 ) : ( 1 \frac { 1 } { 3 } - \frac { 2 } { 3 } )$$

Evaluate

$$-\frac{3}{4}=-0.75$$

Solution Steps

Convert 3 to fraction \frac{6}{2}.

$$\frac{\frac{5}{2}-\frac{6}{2}}{\frac{1\times 3+1}{3}-\frac{2}{3}}$$

Since \frac{5}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{5-6}{2}}{\frac{1\times 3+1}{3}-\frac{2}{3}}$$

Subtract 6 from 5 to get -1.

$$\frac{-\frac{1}{2}}{\frac{1\times 3+1}{3}-\frac{2}{3}}$$

Multiply 1 and 3 to get 3.

$$\frac{-\frac{1}{2}}{\frac{3+1}{3}-\frac{2}{3}}$$

Add 3 and 1 to get 4.

$$\frac{-\frac{1}{2}}{\frac{4}{3}-\frac{2}{3}}$$

Since \frac{4}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-\frac{1}{2}}{\frac{4-2}{3}}$$

Subtract 2 from 4 to get 2.

$$\frac{-\frac{1}{2}}{\frac{2}{3}}$$

Divide -\frac{1}{2} by \frac{2}{3} by multiplying -\frac{1}{2} by the reciprocal of \frac{2}{3}.

$$-\frac{1}{2}\times \frac{3}{2}$$

Multiply -\frac{1}{2} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3}{2\times 2}$$

Do the multiplications in the fraction \frac{-3}{2\times 2}.

$$\frac{-3}{4}$$

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$-\frac{3}{4}$$

Factor

$$-\frac{3}{4} = -0.75$$