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\frac{\frac{3x\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x-1 and x+1 is \left(x-1\right)\left(x+1\right). Multiply \frac{3x}{x-1} times \frac{x+1}{x+1}. Multiply \frac{x}{x+1} times \frac{x-1}{x-1}.
\frac{\frac{3x\left(x+1\right)-x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Since \frac{3x\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} and \frac{x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{3x^{2}+3x-x^{2}+x}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Do the multiplications in 3x\left(x+1\right)-x\left(x-1\right).
\frac{\frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Combine like terms in 3x^{2}+3x-x^{2}+x.
\frac{\left(2x^{2}+4x\right)\left(x^{2}-1\right)}{\left(x-1\right)\left(x+1\right)x}
Divide \frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)} by \frac{x}{x^{2}-1} by multiplying \frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)} by the reciprocal of \frac{x}{x^{2}-1}.
\frac{2x\left(x-1\right)\left(x+1\right)\left(x+2\right)}{x\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
2\left(x+2\right)
Cancel out x\left(x-1\right)\left(x+1\right) in both numerator and denominator.
2x+4
Expand the expression.
\frac{\frac{3x\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x-1 and x+1 is \left(x-1\right)\left(x+1\right). Multiply \frac{3x}{x-1} times \frac{x+1}{x+1}. Multiply \frac{x}{x+1} times \frac{x-1}{x-1}.
\frac{\frac{3x\left(x+1\right)-x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Since \frac{3x\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} and \frac{x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{3x^{2}+3x-x^{2}+x}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Do the multiplications in 3x\left(x+1\right)-x\left(x-1\right).
\frac{\frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)}}{\frac{x}{x^{2}-1}}
Combine like terms in 3x^{2}+3x-x^{2}+x.
\frac{\left(2x^{2}+4x\right)\left(x^{2}-1\right)}{\left(x-1\right)\left(x+1\right)x}
Divide \frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)} by \frac{x}{x^{2}-1} by multiplying \frac{2x^{2}+4x}{\left(x-1\right)\left(x+1\right)} by the reciprocal of \frac{x}{x^{2}-1}.
\frac{2x\left(x-1\right)\left(x+1\right)\left(x+2\right)}{x\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
2\left(x+2\right)
Cancel out x\left(x-1\right)\left(x+1\right) in both numerator and denominator.
2x+4
Expand the expression.