Solve (3/7*2/9)-31/4=

$$( \frac { 3 } { 7 } \cdot \frac { 2 } { 9 } ) - 3 \frac { 1 } { 4 } =$$

Evaluate

$$-\frac{265}{84}\approx -3.154761905$$

Solution Steps

Multiply \frac{3}{7} times \frac{2}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 2}{7\times 9}-\frac{3\times 4+1}{4}$$

Do the multiplications in the fraction \frac{3\times 2}{7\times 9}.

$$\frac{6}{63}-\frac{3\times 4+1}{4}$$

Reduce the fraction \frac{6}{63} to lowest terms by extracting and canceling out 3.

$$\frac{2}{21}-\frac{3\times 4+1}{4}$$

Multiply 3 and 4 to get 12.

$$\frac{2}{21}-\frac{12+1}{4}$$

Add 12 and 1 to get 13.

$$\frac{2}{21}-\frac{13}{4}$$

Least common multiple of 21 and 4 is 84. Convert \frac{2}{21} and \frac{13}{4} to fractions with denominator 84.

$$\frac{8}{84}-\frac{273}{84}$$

Since \frac{8}{84} and \frac{273}{84} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-273}{84}$$

Subtract 273 from 8 to get -265.

$$-\frac{265}{84}$$

Factor

$$-\frac{265}{84} = -3\frac{13}{84} = -3.1547619047619047$$