Solve (3/4)^2+(4/3)^-2*(-3)^2/4:3/4^2=

$$( \frac { 3 } { 4 } ) ^ { 2 } + ( \frac { 4 } { 3 } ) ^ { - 2 } \cdot \frac { ( - 3 ) ^ { 2 } } { 4 } : \frac { 3 } { 4 ^ { 2 } } =$$

Evaluate

$$\frac{117}{16}=7.3125$$

Solution Steps

Calculate \frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$\frac{9}{16}+\frac{\left(\frac{4}{3}\right)^{-2}\times \frac{\left(-3\right)^{2}}{4}}{\frac{3}{4^{2}}}$$

Calculate \frac{4}{3} to the power of -2 and get \frac{9}{16}.

$$\frac{9}{16}+\frac{\frac{9}{16}\times \frac{\left(-3\right)^{2}}{4}}{\frac{3}{4^{2}}}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{9}{16}+\frac{\frac{9}{16}\times \frac{9}{4}}{\frac{3}{4^{2}}}$$

Multiply \frac{9}{16} and \frac{9}{4} to get \frac{81}{64}.

$$\frac{9}{16}+\frac{\frac{81}{64}}{\frac{3}{4^{2}}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{9}{16}+\frac{\frac{81}{64}}{\frac{3}{16}}$$

Divide \frac{81}{64} by \frac{3}{16} by multiplying \frac{81}{64} by the reciprocal of \frac{3}{16}.

$$\frac{9}{16}+\frac{81}{64}\times \frac{16}{3}$$

Multiply \frac{81}{64} and \frac{16}{3} to get \frac{27}{4}.

$$\frac{9}{16}+\frac{27}{4}$$

Add \frac{9}{16} and \frac{27}{4} to get \frac{117}{16}.

$$\frac{117}{16}$$

Factor

$$\frac{3 ^ {2} \cdot 13}{2 ^ {4}} = 7\frac{5}{16} = 7.3125$$