Solve (3/2x^3+4/3)+(4/2x^2+2/4)

$$( \frac { 3 } { 2 } x ^ { 3 } + \frac { 4 } { 3 } ) + ( \frac { 4 } { 2 } x ^ { 2 } + \frac { 2 } { 4 } )$$

Evaluate

$$\frac{3x^{3}}{2}+2x^{2}+\frac{11}{6}$$

Solution Steps

Divide 4 by 2 to get 2.

$$\frac{3}{2}x^{3}+\frac{4}{3}+2x^{2}+\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}x^{3}+\frac{4}{3}+2x^{2}+\frac{1}{2}$$

Add \frac{4}{3} and \frac{1}{2} to get \frac{11}{6}.

$$\frac{3}{2}x^{3}+\frac{11}{6}+2x^{2}$$

Factor

$$\frac{9x^{3}+12x^{2}+11}{6}$$

Solution Steps

Factor out \frac{1}{6}. Polynomial 9x^{3}+12x^{2}+11 is not factored since it does not have any rational roots.

$$\frac{9x^{3}+11+12x^{2}}{6}$$