Solve (3^4*3^2/3^5)^-3=

$$( \frac { 3 ^ { 4 } \cdot 3 ^ { 2 } } { 3 ^ { 5 } } ) ^ { - 3 } =$$

Evaluate

$$\frac{1}{27}\approx 0.037037037$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 4 and 2 to get 6.

$$\left(\frac{3^{6}}{3^{5}}\right)^{-3}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 5 from 6 to get 1.

$$\left(3^{1}\right)^{-3}$$

Calculate 3 to the power of 1 and get 3.

$$3^{-3}$$

Calculate 3 to the power of -3 and get \frac{1}{27}.

$$\frac{1}{27}$$

Factor

$$\frac{1}{3 ^ {3}} = 0.037037037037037035$$