Solve (3^-2/4^-3)(4/3)^-2

$$( \frac { 3 ^ { - 2 } } { 4 ^ { - 3 } } ) ( \frac { 4 } { 3 } ) ^ { - 2 }$$

Evaluate

$$4$$

Solution Steps

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{\frac{1}{9}}{4^{-3}}\times \left(\frac{4}{3}\right)^{-2}$$

Calculate 4 to the power of -3 and get \frac{1}{64}.

$$\frac{\frac{1}{9}}{\frac{1}{64}}\times \left(\frac{4}{3}\right)^{-2}$$

Divide \frac{1}{9} by \frac{1}{64} by multiplying \frac{1}{9} by the reciprocal of \frac{1}{64}.

$$\frac{1}{9}\times 64\times \left(\frac{4}{3}\right)^{-2}$$

Multiply \frac{1}{9} and 64 to get \frac{64}{9}.

$$\frac{64}{9}\times \left(\frac{4}{3}\right)^{-2}$$

Calculate \frac{4}{3} to the power of -2 and get \frac{9}{16}.

$$\frac{64}{9}\times \frac{9}{16}$$

Multiply \frac{64}{9} and \frac{9}{16} to get 4.

$$4$$

Factor

$$2^{2}$$